The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF).

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

f(c(X, s(Y))) → f(c(s(X), Y))
g(c(s(X), Y)) → f(c(X, s(Y)))

Rewrite Strategy: FULL

(1) DecreasingLoopProof (EQUIVALENT transformation)

The following loop(s) give(s) rise to the lower bound Ω(n¹):
The rewrite sequence
f(c(X, s(Y))) →⁺ f(c(s(X), Y))
gives rise to a decreasing loop by considering the right hand sides subterm at position [].
The pumping substitution is [Y / s(Y)].
The result substitution is [X / s(X)].

(2) BOUNDS(n^1, INF)

(3) RenamingProof (EQUIVALENT transformation)

Renamed function symbols to avoid clashes with predefined symbol.

(4) Obligation:

Runtime Complexity Relative TRS:
The TRS R consists of the following rules:

f(c(X, s(Y))) → f(c(s(X), Y))
g(c(s(X), Y)) → f(c(X, s(Y)))

S is empty.
Rewrite Strategy: FULL

(5) TypeInferenceProof (BOTH BOUNDS(ID, ID) transformation)

Infered types.

(6) Obligation:

TRS:
Rules:
f(c(X, s(Y))) → f(c(s(X), Y))
g(c(s(X), Y)) → f(c(X, s(Y)))

Types:
f :: c → f:g
c :: s → s → c
s :: s → s
g :: c → f:g
hole_f:g1_0 :: f:g
hole_c2_0 :: c
hole_s3_0 :: s
gen_s4_0 :: Nat → s

(7) OrderProof (LOWER BOUND(ID) transformation)

Heuristically decided to analyse the following defined symbols:
f

(8) Obligation:

TRS:
Rules:
f(c(X, s(Y))) → f(c(s(X), Y))
g(c(s(X), Y)) → f(c(X, s(Y)))

Types:
f :: c → f:g
c :: s → s → c
s :: s → s
g :: c → f:g
hole_f:g1_0 :: f:g
hole_c2_0 :: c
hole_s3_0 :: s
gen_s4_0 :: Nat → s

Generator Equations:
gen_s4_0(0) ⇔ hole_s3_0
gen_s4_0(+(x, 1)) ⇔ s(gen_s4_0(x))

The following defined symbols remain to be analysed:
f

(9) NoRewriteLemmaProof (LOWER BOUND(ID) transformation)

Could not prove a rewrite lemma for the defined symbol f.

(10) Obligation:

TRS:
Rules:
f(c(X, s(Y))) → f(c(s(X), Y))
g(c(s(X), Y)) → f(c(X, s(Y)))

Types:
f :: c → f:g
c :: s → s → c
s :: s → s
g :: c → f:g
hole_f:g1_0 :: f:g
hole_c2_0 :: c
hole_s3_0 :: s
gen_s4_0 :: Nat → s

Generator Equations:
gen_s4_0(0) ⇔ hole_s3_0
gen_s4_0(+(x, 1)) ⇔ s(gen_s4_0(x))

No more defined symbols left to analyse.